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TensorFlow 1 version
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View source on GitHub
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Computes the standard deviation of elements across dimensions of a tensor.
tf.math.reduce_std(
input_tensor, axis=None, keepdims=False, name=None
)
Used in the notebooks
| Used in the tutorials |
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Reduces input_tensor along the dimensions given in axis.
Unless keepdims is true, the rank of the tensor is reduced by 1 for each
of the entries in axis, which must be unique. If keepdims is true, the
reduced dimensions are retained with length 1.
If axis is None, all dimensions are reduced, and a
tensor with a single element is returned.
For example:
x = tf.constant([[1., 2.], [3., 4.]])tf.math.reduce_std(x)<tf.Tensor: shape=(), dtype=float32, numpy=1.118034>tf.math.reduce_std(x, 0)<tf.Tensor: shape=(2,), dtype=float32, numpy=array([1., 1.], dtype=float32)>tf.math.reduce_std(x, 1)<tf.Tensor: shape=(2,), dtype=float32, numpy=array([0.5, 0.5], dtype=float32)>
Args | |
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input_tensor
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The tensor to reduce. Should have real or complex type. |
axis
|
The dimensions to reduce. If None (the default), reduces all
dimensions. Must be in the range [-rank(input_tensor),
rank(input_tensor)).
|
keepdims
|
If true, retains reduced dimensions with length 1. |
name
|
A name scope for the associated operations (optional). |
Returns | |
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The reduced tensor, of the same dtype as the input_tensor. Note, for
complex64 or complex128 input, the returned Tensor will be of type
float32 or float64, respectively.
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Numpy Compatibility
Equivalent to np.std
Please note np.std has a dtype parameter that could be used to specify the
output type. By default this is dtype=float64. On the other hand,
tf.math.reduce_std has aggressive type inference from input_tensor.