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TensorFlow 1 version
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View source on GitHub
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Computes the sum along segments of a tensor divided by the sqrt(N).
tf.math.unsorted_segment_sqrt_n(
data, segment_ids, num_segments, name=None
)
Read the section on segmentation for an explanation of segments.
This operator is similar to the tf.math.unsorted_segment_sum operator.
Additionally to computing the sum over segments, it divides the results by
sqrt(N).
\(output_i = 1/sqrt(N_i) \sum_{j...} data[j...]\) where the sum is over
tuples j... such that segment_ids[j...] == i with \N_i\ being the
number of occurrences of id \i\.
If there is no entry for a given segment ID i, it outputs 0.
Note that this op only supports floating point and complex dtypes, due to tf.sqrt only supporting these types.
If the given segment ID i is negative, the value is dropped and will not
be added to the sum of the segment.
Args | |
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data
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A Tensor with floating point or complex dtype.
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segment_ids
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An integer tensor whose shape is a prefix of data.shape.
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num_segments
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An integer scalar Tensor. The number of distinct segment
IDs.
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name
|
A name for the operation (optional). |
Returns | |
|---|---|
A Tensor. Has same shape as data, except for the first segment_ids.rank
dimensions, which are replaced with a single dimension which has size
num_segments.
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