TensorFlow 1 version | View source on GitHub |
Computes the sum along segments of a tensor divided by the sqrt(N).
tf.math.unsorted_segment_sqrt_n(
data, segment_ids, num_segments, name=None
)
Read the section on segmentation for an explanation of segments.
This operator is similar to the tf.math.unsorted_segment_sum
operator.
Additionally to computing the sum over segments, it divides the results by
sqrt(N).
\(output_i = 1/sqrt(N_i) \sum_{j...} data[j...]\) where the sum is over
tuples j...
such that segment_ids[j...] == i
with \N_i\ being the
number of occurrences of id \i\.
If there is no entry for a given segment ID i
, it outputs 0.
Note that this op only supports floating point and complex dtypes, due to tf.sqrt only supporting these types.
If the given segment ID i
is negative, the value is dropped and will not
be added to the sum of the segment.
Args | |
---|---|
data
|
A Tensor with floating point or complex dtype.
|
segment_ids
|
An integer tensor whose shape is a prefix of data.shape .
|
num_segments
|
An integer scalar Tensor . The number of distinct segment
IDs.
|
name
|
A name for the operation (optional). |
Returns | |
---|---|
A Tensor . Has same shape as data, except for the first segment_ids.rank
dimensions, which are replaced with a single dimension which has size
num_segments .
|